Ethanal \( \left(\mathrm{CH}_{3} \mathrm{CHO}\right) \) reacts with \( \mathrm{NaBH}_{4} \), followed by \( \mathrm{H}_{3} \mathrm{O}^{+} \)to give an alcohol product. The product of this reaction will be:
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In this reaction, we have ethanal (\( \mathrm{CH}_{3} \mathrm{CHO} \)) and sodium borohydride (\( \mathrm{NaBH}_{4} \)) as the initial reactants. Ethanal is an aldehyde, and \( \mathrm{NaBH}_{4} \) is a reducing agent. Show more…
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