Ethyl alcohol is prepared industrially by the reaction of ethylene, C2H4 , with water. What is the percent yield of the reaction if 4.6 g of ethylene gives 4.7 g of ethyl alcohol? C2H4 (g) +H2O(l) hC2H6O(l) Ethylene Ethyl alcohol
Added by Heather H.
Step 1
The molar mass of ethylene (C2H4) = (2*12.01 g/mol) + (4*1.008 g/mol) = 28.052 g/mol The molar mass of ethyl alcohol (C2H6O) = (2*12.01 g/mol) + (6*1.008 g/mol) + (16.00 g/mol) = 46.068 g/mol Show more…
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