Étudiez la convergence de la série \(\sum_{n=1}^{\infty} (-1)^n \frac{n+2}{n^2+1}\)
Added by Haley S.
Close
Step 1
We can see that the general term of the series is (-1)^(n+1) * 4 * 2^n. Show more…
Show all steps
Your feedback will help us improve your experience
Manisha Sarker and 91 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find the sum of the convergent series. $\sum_{n=1}^{\infty} \frac{8}{(n+1)(n+2)}$
Infinite Series
Series and Convergence
Determine the convergence or divergence of the series. $$\sum_{n=1}^{\infty}\left(\frac{1}{n}-\frac{1}{n+2}\right)$$
Summation n=1 to infinity (n+1)/ (n^4 +2) check for convergence
Melissa M.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD