00:01
Let's evaluate this definite integral of x times of e power x squared plus 2.
00:07
And the limits are from x equal to 0 to x equal to 1.
00:11
So i'm going to evaluate this definite integral using substitution method.
00:16
That is, i'm going to substitute this x squared as u.
00:21
So let's do that.
00:23
Let's put x squared equals u.
00:25
Now we take the derivative on both sides.
00:28
The derivative of x squared using power rule is 2x times dx and this equals the derivative of u is d u let's solve for x dx we have x d x and this equals d u over 2 we solve this specifically for x d x because we have x and d x these two are product which means that we can replace that as d u over 2 so let's apply the substitution and so so therefore this different integral will become integral from x dx is du by 2.
01:04
I write this as du by 2 for x times of d x.
01:09
And then e to the power replace x squared by u.
01:12
So this will become e power u and then plus 2.
01:16
I'm just finding the indefinite integral.
01:19
I'm not writing the limits because we will have to integrate this first with respect to you and then apply the same limit of x.
01:28
After doing the back substitution of you.
01:30
So let's evaluate this indefinite integral...