Evaluate.\n\(\int_0^6 15\sqrt{4x+1} dx\)\n\(\int_0^6 15\sqrt{4x+1} dx = \square\) (Simplify your answer.)
Added by Juan Manuel R.
Close
Step 1
Then, du = 4dx, which means dx = du/4. Substituting these into the integral, we get: \int_0^6 15\sqrt(4x+1)dx = 15 * \int_0^6 \sqrt(u) * (1/4) du = (15/4) * \int_0^6 \sqrt(u) du Show more…
Show all steps
Your feedback will help us improve your experience
Sri K and 92 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Evaluate the expression: 6C5 / 14C5 (Simplify your answer.)
Sri K.
Steven C.
Evaluate each expression. $$\frac{2(1.242)+0.8932}{0.4-0.8}$$
Jessica K.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD