00:01
In this question we recall that the integral from a to p on the function fx, dx can be written down in terms of the limit.
00:10
Summation i goes from 1 up to n, f under ci times delta xi.
00:17
In this question here, we are given the integral from minus 2 to 3, and we have the x tx.
00:29
Here if we set the ci, here we use a lower power to be minus 2, and then we plus with the 3 minus 2 over n times i, then we get ci equal to the minus 2 plus 5i over n.
00:52
So when we get the ci, we can find the delta xi equal to here the minus 2 plus 5i over n.
01:02
5 i over n then minus the minus 2 plus 5 i minus 1 over n then we get equal to 2 here cancel out and then we get equal to the n in the common denominator then we have 5 i so we have a 1 here 5 here over n and then we can look in into the integral here and we get a little and goes to infinity summation i goes from 1 up to n then we have this one we have the c i already so this will be the function fx so we can equal to the minus 2 plus 5 i over n times delta x i will be 5 over n and this limit it will equal to the limit and we goes to infinity, summation i goes from 1 up to n.
02:05
And it will simplify we get equal to the minus 10 over n...