Question

Evaluate the definite integral $\int_0^{\frac{5\pi}{3}} 14\sin(x)dx$ using Part 1 of the Fundamental Theorem of Calculus. $\int_0^{\frac{5\pi}{3}} 14\sin(x)dx$ = Number

          Evaluate the definite integral
$\int_0^{\frac{5\pi}{3}} 14\sin(x)dx$
using Part 1 of the Fundamental Theorem of Calculus.
$\int_0^{\frac{5\pi}{3}} 14\sin(x)dx$ = Number

Evaluate the definite integral
∫0^(5π)/(3) 14sin(x)dx
using Part 1 of the Fundamental Theorem of Calculus.
∫0^(5π)/(3) 14sin(x)dx = Number

Added by Susan S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Luke Humphrey

04/19/2024

Step 1

The antiderivative of $\sin(x)$ is $-\cos(x)$. Therefore, the antiderivative of $14\sin(x)$ is $-14\cos(x)$. Show more…

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Evaluate the definite integral $$\int_{0}^{\frac{5\pi}{3}} 14 \sin(x) dx$$ using Part 1 of the Fundamental Theorem of Calculus. $$\int_{0}^{\frac{5\pi}{3}} 14 \sin(x) dx = \text{Number}$$