Evaluate the definite integral of $\int_{-3}^{3} f(x) dx$ for $f(x) = \begin{cases} -x+1 & \text{if } -3 \le x < 0\\ 4x+1, & \text{if } 0 \le x \le 3 \end{cases}$
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Step 1: Since the function is defined piecewise, we need to split the integral into two parts: $\int_{-3}^3 f(x) dx = \int_{-3}^0 f(x) dx + \int_0^3 f(x) dx$ Show more…
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