00:01
Hello students in sixth question having two parts.
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First part given that f of x comma y equals x plus y, the region that lies left to the y axis between the circles, x squared plus y square equals 1 and x squared plus y square equals 4.
00:21
We need to let x equals r cost theta and y equals or sine 3.
00:32
So that we get dx, d -x, d -y equals r, d -r -d -theta.
00:39
And here, limits from 1 less than r -less than r -less -than -r -than - or equal to 2, and theta varies from pi -by -2 to 3 -py -by -2.
00:54
Therefore, double integral over r -x plus y, d -a, can be written as integral over pi by 2 to 3 pi by 2 integral over 1 to 2 and x can be written as r cos theta plus y can be written as r sine theta into d a s d x d y so it will be written as r d r d theta on integrating with respect to r, then we get integral over pi by 2 to 3 pi by 2.
01:39
Here, cost theta plus sine theta into r...