Evaluate the double integral. $$ \iint_D 6xy^2 \, dA $$ D is enclosed by $$ x = 0 $$ and $$ x = \sqrt{4-y^2} $$
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First, let's understand the region D. The equation $$ x = \sqrt{4-y^2} $$ implies $$ x^2 = 4-y^2 $$ (since $$ x \ge 0 $$), which can be rewritten as $$ x^2 + y^2 = 4 $$. This is the equation of a circle centered at the origin with radius 2. Since $$ x = Show more…
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