Question

Evaluate the following integral.\\ $\int \frac{x+3}{x^2 + 6x + 16} dx$\\ $\int \frac{x+3}{x^2 + 6x + 16} dx = $

          Evaluate the following integral.\\
$\int \frac{x+3}{x^2 + 6x + 16} dx$\\
$\int \frac{x+3}{x^2 + 6x + 16} dx = $

Evaluate the following integral.

∫(x+3)/(x^2 + 6x + 16) dx

∫(x+3)/(x^2 + 6x + 16) dx =

Added by Jason V.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Israel Hernandez

07/04/2022

Step 1

Step 1: Rewrite the integrand as a sum of two fractions: \int \frac{x+3}{x^2+6x+16} dx = \int \frac{x}{x^2+6x+16} dx + \int \frac{3}{x^2+6x+16} dx Show more…

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Evaluate the following integral. int (x+3)/(x^(2)+6x+16)dx int (x+3)/(x^(2)+6x+16)dx= Evaluate the following integral. x+3 dx +6+16 x+3 dx= 2 X +6+16

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Evaluate the following integral.\\ $\int \frac{x+3}{x^2 + 6x + 16} dx$\\ $\int \frac{x+3}{x^2 + 6x + 16} dx = $

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