Evaluate the following integral.\\ $\int_0^1 \frac{1}{\sqrt{36x^2 + 1764}} dx$\\ Enter your answer as an exact answer. Be sure\\ to include the argument of the trigonometric\\ function in parentheses.\\ Provide your answer below:\\ $\int_0^1 \frac{1}{\sqrt{36x^2 + 1764}} dx = $
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Step 1: We can rewrite the integral as follows: $$\int_0^1 \frac{1}{\sqrt{36x^2 + 1764}} dx = \int_0^1 \frac{1}{\sqrt{36(x^2 + 49)}} dx = \frac{1}{6} \int_0^1 \frac{1}{\sqrt{x^2 + 49}} dx$$ Show more…
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