00:01
All right, we have the integral of d .y over y to the minus 1 plus y to the minus 3.
00:12
That's the same as dy over 1 over y plus 1 over y cubed.
00:21
So that's integral dx over y squared plus 1 over y cubed.
00:33
So that's integral of y cubed over y squared plus 1 dx.
00:38
Now let's do long division.
00:40
So that's y cubed plus 0 y squared.
00:43
I'm putting placeholders here plus 0 divided by y squared plus 0 plus 1.
00:52
So that'll be y here.
00:54
It's y cubed, 0 y squared and y.
00:58
So subtracting here will get negative y as a remainder.
01:03
So now this can be rewritten as integral of y minus y.
01:12
Over y squared plus 1...