Evaluate the following integral using trigonometric substitution.\ $int frac{dx}{(441 + x^2)^{frac{3}{2}}}$
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Then, we have: $$\int \frac{21\sec^2(\theta)d\theta}{\sqrt{441+2(21\tan(\theta))^2}}$$ Simplify the expression inside the square root: $$\sqrt{441+2(21\tan(\theta))^2} = \sqrt{441+882\tan^2(\theta)}$$ Now, use the identity $\tan^2(\theta) + 1 = Show more…
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