Evaluate the following integral using trigonometric substitution. $$ \int \frac{dx}{\sqrt{x^2 - 9}}, x > 3 $$ What substitution will be the most helpful for evaluating this integral? A. x = 3 tan θ B. x = 3 sec θ C. x = 3 sin θ Rewrite the given integral using this substitution. $$ \int \frac{dx}{\sqrt{x^2 - 9}} = \int \boxed{} d\theta $$ (Type an exact answer.)
Added by Mark E.
Close
Step 1
This suggests using the trigonometric substitution $x = 3 \sec \theta$. Show more…
Show all steps
Your feedback will help us improve your experience
T. L. and 72 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
T. L.
Evaluate the integral using the indicated trigonometric substitution. Sketch and label the associated right triangle. $\int \frac{x^{3}}{\sqrt{9+x^{2}}} d x \quad x=3 \tan \theta$
Techniques of Integration
Trigonometric Substitution
evaluate the given integrals using trigonometric substitution
Nick J.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD