Evaluate the following limit (if possible) $\lim_{x \to 0} \frac{5 \sin^3(4x)}{7x^3}$ A 0 B Does not exist. C $\frac{320}{343}$ D $\frac{320}{7}$ E $\frac{20}{7}$ F None of the above.
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Step 1: To evaluate the limit \lim_(x->0)(5sin^(3)(4x))/(7x^(3)), we can first simplify the expression by using the trigonometric identity sin^3(x) = (3sin(x) - sin(3x))/4. Show more…
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