Question

Evaluate the following limit. Use l'Hôpital's Rule when it is convenient and applicable. lim x?-7 (x² + 16x + 63) / (-63 - 2x + x²) Use l'Hôpital's Rule to rewrite the given limit so that it is not an indeterminate form. lim x?-7 (x² + 16x + 63) / (-63 - 2x + x²) = lim x?-7 ( )

          Evaluate the following limit. Use l'Hôpital's Rule when it is convenient and applicable.
lim x?-7 (x² + 16x + 63) / (-63 - 2x + x²)
Use l'Hôpital's Rule to rewrite the given limit so that it is not an indeterminate form.
lim x?-7 (x² + 16x + 63) / (-63 - 2x + x²) = lim x?-7 ( )

Evaluate the following limit. Use l'Hôpital's Rule when it is convenient and applicable.
lim x?-7 (x² + 16x + 63) / (-63 - 2x + x²)
Use l'Hôpital's Rule to rewrite the given limit so that it is not an indeterminate form.
lim x?-7 (x² + 16x + 63) / (-63 - 2x + x²) = lim x?-7 ( )

Added by Kelli A.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Vishal Parmar

04/16/2022

Step 1

Step 1: Apply L'Hopital's Rule by taking the derivative of the numerator and denominator separately. Show more…

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Evaluate the following limit. Use l'Hôpital's Rule when it is convenient and applicable. lim x -> -7 (x^2 + 16x + 63) / (-63 - 2x + x^2) Use l'Hôpital's Rule to rewrite the given limit so that it is not an indeterminate form. lim x -> -7 (x^2 + 16x + 63) / (-63 - 2x + x^2) = lim x -> -7 ( )