00:01
Allow student here we have to evaluate the following limits right first question is first question limit as x tends to infinity x tends to infinity 3x square plus 7 divide by right 3x plus 2 x square right now this one can be written as limit as x to infinity.
00:28
If we take x square common in numerator, what will get 3 plus 7 divided by x squared, 2, 2, if you take here x, x square, right? if you take here x, x square common, we will get 3 divided by x plus 2.
00:45
Now here x square, x squared cancel as x tends to infinity, we will get 3 plus 0, divide by 0, plus 2.
00:55
We will get 3, 3 divide by 2.
00:58
This is our required answer.
01:01
Right.
01:01
Next question is question number 2.
01:05
Right limit as x tends to infinity.
01:08
X tends to infinity 3x plus 1 divide by right x cube plus 2x square right plus 1.
01:21
Now this one can be written as limit as x tends to infinity.
01:26
In numerator, i'm going to to take x common we will get 3 plus 1 divide by x all divide by right if we take x cube common here what we'll get 1 plus 2 divide by x plus right 1 divide by x square now here on x on x get cancelled as x tends to infinity right this term become 0 this is 0 this is 0 so you will get 1, right, anything by infinity is 0...