00:01
In this question, let i equals to integration from minus 5 to 0 mod of x plus 3 dx.
00:09
Now, if x equals to minus 5, so minus 5 plus 3, this is equals to minus 2 which is a negative and if x equals to minus 4, so minus 4 plus 3 and this is equals to minus 1.
00:28
Again, it is a negative.
00:30
So, from here this will be break into interval i equals to minus of integration from minus 5 to minus 4 and this function x plus 3 will be negative and dx.
00:45
Then, next to plus integration from minus 4, so minus 4 to 0 and this function will be positive, x plus 3 dx.
00:58
Then, after further simplifying, this will be minus of x square by 2 plus 3x and the limit is from minus 5 to minus 4 and here it will be plus, this will be x square by 2 plus 3x and the limit is from minus 4 to 0.
01:20
So, on substituting the limit, i equals to minus of square of minus 4 that will be 16 minus square of 5 that will be 25 divided by 2 and plus 3 times of minus 4 in minus minus plus 5 and here it will be plus square of 0 which is a 0 and minus square of minus 4 that will be plus 16 divided by 2 plus 3 times of 0 minus and minus plus 4.
01:53
So, this is equals to minus and here it will be 16 plus 4 and here it is plus 5...