Problem 10. (3 points) Evaluate the indefinite integral $\int \frac{-3 \arctan(x)}{1 + x^2} dx$
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Let u = -3arctan(x) and dv = 1/(1+x^2)dx. Then, differentiate u to get du = -3/(1+x^2)dx and integrate dv to get v = arctan(x). Show more…
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