Evaluate the integral.\\ $\int_{1/\sqrt{3}}^{\sqrt{3}} \frac{2}{1+x^2} dx$\\ $-ln(\frac{3\sqrt{3}+3}{\sqrt{3}+3}) + ln(-\frac{3\sqrt{3}-3}{\sqrt{3}-3})$
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Step 1: First, simplify the given integral: β«(β3 2 (1/3x + x^(1/3) + 3 - ln(1)) + ln(3β3) 3 β3 - 3 β3 + 3) dx Show moreβ¦
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