Evaluate the integral. [ int_{0}^{1} frac{x^{3}-2 x-7}{x^{2}-x-6} d x ]
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Step 1: Simplify the expression by dividing the numerator by the denominator: \[ \frac{x^3 - 2x - 7}{x^2 - x - 6} = \frac{x^2 + 4x - 7}{x + 1} = x + 1 + \frac{5x - 1}{x^2 - x - 6} \] Show more…
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