Evaluate the integral by eliminating the square root. Hint: Use double-angle identity for cosine. \(14) \int_0^{\frac{\pi}{6}} \sqrt{1 + \cos 6\theta} d\theta\)
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The double angle identity for cosine is given by: cos(2θ) = 1 - 2sin^2(θ) In this case, we have cos(6θ), so we can rewrite it as: cos(6θ) = 1 - 2sin^2(3θ) Show more…
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