Question

Evaluate the integral \(\int x^6 (x^7 - 4)^{16} dx\), \\ by making the appropriate substitution: u = \\ \(\int x^6 (x^7 - 4)^{16} dx = \frac{1}{119} (x^7 - 4)^{17} + C\\ NOTE: Your answer should be in terms of x and not u.

          Evaluate the integral \(\int x^6 (x^7 - 4)^{16} dx\), \\ by making the appropriate substitution: u = \\
\(\int x^6 (x^7 - 4)^{16} dx = \frac{1}{119} (x^7 - 4)^{17} + C\\
NOTE: Your answer should be in terms of x and not u.

Evaluate the integral ∫ x^6 (x^7 - 4)^16 dx,
by making the appropriate substitution: u =

∫ x^6 (x^7 - 4)^16 dx = (1)/(119) (x^7 - 4)^17 + C

NOTE: Your answer should be in terms of x and not u.

Added by Cory O.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Keerti J

Step 1

First, let's rewrite the integral in terms of u: dx = du / (2 * √(e^7 - 4)) Now, substitute this into the integral: ∫(dx / √(e^7 - 4)) = ∫(du / (2 * √(e^7 - 4))) Since the integral of du is just u, we have: ∫(du / (2 * √(e^7 - 4))) = u / (2 * √(e^7 - 4)) Show more…

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