Question

Evaluate the integral by reversing the order of integration.\\ $\int_0^1 \int_{5y}^5 e^{x^2} dx dy = $

          Evaluate the integral by reversing the order of integration.\\
$\int_0^1 \int_{5y}^5 e^{x^2} dx dy = $
        
Evaluate the integral by reversing the order of integration.

∫0^1 ∫5y^5 e^x^2 dx dy =

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Evaluate the integral by reversing the order of integration. int_0^1 int_(5y)^5 e^(x^(2))dxdy= Evaluate the integral by reversing the order of integration c5
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Transcript

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00:01 We have to find the value of the integral i equals to integration from y is equal to 0 to y is equal to 8 integration from x is equal to cube root of y to x is equal to 2, 3, e to the power x to the power 4 dx dy.
00:24 So, first of all, we can see that the region of integration is bounded by x is equal to cube root of y, x is equal to 2, y is equal to 0 and y is equal to 8.
01:01 So, first of all, we will draw the curve, this is y axis and this is x axis and this is the curve.
01:13 So, the value of x is changing from 2 to the curve that is cube root of y and the value of y is changing from 8 to 0.
01:27 So, we have to find out the area of this region.
01:30 So, we can write on changing the order of integration, the new limits are y is changing from 0 to x cube and x is changing from 0 to 2...
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