Question

Evaluate the integral $\int e^{2x} dx$. $\int e^{2x} dx = 2e^{2x} + C$ $\int e^{2x} dx = 2e^x + C$ $\int e^{2x} dx = \frac{1}{2e^{2x}} + C$ $\int e^{2x} dx = \frac{1}{2}e^{2x} + C$ $\int e^{2x} dx = e^{2x} + C$

          Evaluate the integral $\int e^{2x} dx$.
$\int e^{2x} dx = 2e^{2x} + C$
$\int e^{2x} dx = 2e^x + C$
$\int e^{2x} dx = \frac{1}{2e^{2x}} + C$
$\int e^{2x} dx = \frac{1}{2}e^{2x} + C$
$\int e^{2x} dx = e^{2x} + C$

Evaluate the integral ∫ e^2x dx.
∫ e^2x dx = 2e^2x + C
∫ e^2x dx = 2e^x + C
∫ e^2x dx = (1)/(2e^2x) + C
∫ e^2x dx = (1)/(2)e^2x + C
∫ e^2x dx = e^2x + C

Added by Matthew S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Rukhmani Jain

12/09/2021

Step 1

Step 1: The integral of e^(2x) with respect to x is given by: ∫ e^(2x) dx = (1/2)e^(2x) + C, where C is the constant of integration. Show more…

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Evaluate the integral int e^(2x)dx int e^(2x)dx=2e^(2x)+C int e^(2x)dx=2e^(x)+C int e^(2x)dx=(1)/(2e^(2x))+C int e^(2x)dx=(1)/(2)e^(2x)+C int e^(2x)dx=e^(2x)+C Evaluate the integral e2 dx. e2dx=2e2x+C e2dx=2e+C 1 +0 2e2x 112 e2dx=e2x+C