Evaluate the integral. $$ \int \frac{(4x - 7) dx}{x^2 - 9x + 20} $$ (Use symbolic notation and fractions where needed. Use C for the arbitrary constant.) $$ \int \frac{(4x - 7) dx}{x^2 - 9x + 20} = $$
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Let's try to see if a simple substitution works. Let $u = x^2 - 9x + 20$. Then $du = (2x - 9) dx$. The numerator is $4x - 7$. We need to relate $4x - 7$ to $2x - 9$. We can write $4x - 7 = 2(2x - 9) + 18 - 7 = 2(2x - 9) + 11$. So the integral becomes: $$ \int Show more…
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