00:01
Okay, on this problem, first thing to do is factor the denominator.
00:07
Okay, two numbers that multiply together give you positive six, add together, give you negative 5.
00:13
That means they're both negative, so negative 2 and negative 3.
00:21
So a over x minus 2 plus b over x minus 3 equals x minus 4 over x minus 2, x minus 3, multiply by that denominator.
00:41
That gives you a times x minus 3 plus b times x minus 2 equals x minus 4.
00:51
So you can multiply this out and get a system of equations and solve.
00:56
I can just do some substitutions.
00:58
So i'm going to let xb3, and i chose 3 because that will make this factor be 0.
01:04
And you get a times 0 plus b times 1 equals negative...