00:01
Hi there.
00:01
So for this problem, we have the integral of x square times x to the 3 minus 6.
00:08
This, elevated to the 4 integral over x.
00:13
So for this, we choose that u is equal to x to the 3 minus 8.
00:20
So what we are doing today is substitution, okay? now we take the derivative of this.
00:24
The derivative of x to the 3 is that we take down the 3 and subtract 1 unit to the exponential.
00:30
That i will give us three times adds a square.
00:33
Now, with that we will have then, and that you can recognize, well, let me just solve in here.
00:39
Oh, sorry, i forgot the d -framecial and x.
00:41
We can solve for the differential and adds.
00:48
Ets squared times the d -framcial and ets because you can recognize in here that we have this, which is this in here.
00:55
And then solving in here for data will be the differential you divided by three...