Question

Evaluate the integral using partial fractions ʃ (x + 1) dx / ( x^3 + x^2 – 6x ) Format: ʃ A/x + ʃ B/(x – 2) + ʃ C/(x + 3)

Name: evaluate the integral using partial fractions x 1 dx x3 x2 6x format ax bx 2 cx 3
Uploaded: 2022-07-13T04:08:00-08:00
Duration: 5 min 15 s
Channel: Steven Clarke
Description: evaluate the integral using partial fractions x 1 dx x3 x2 6x format ax bx 2 cx 3

          Evaluate the integral using  partial fractions
ʃ (x + 1) dx / ( x^3 + x^2 – 6x )
Format: ʃ A/x  + ʃ B/(x – 2) + ʃ C/(x + 3)

Added by Reznick J.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Steven Clarke

07/13/2022

Step 1

Step 1:** Factorize the denominator: \(x^3 + x^2 - 6x = x(x^2 + x - 6) = x(x + 3)(x - 2)\) ** Show more…

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Evaluate the integral using partial fractions ʃ (x + 1) dx / ( x^3 + x^2 – 6x ) Format: ʃ A/x + ʃ B/(x – 2) + ʃ C/(x + 3)

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Evaluate the integral using partial fractions ʃ (x + 1) dx / ( x^3 + x^2 – 6x ) Format: ʃ A/x + ʃ B/(x – 2) + ʃ C/(x + 3)

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