Question

Evaluate the limit. (Use symbolic notation and fractions where needed.) $\lim_{x \to -\infty} \frac{7 + 6e^{(2x)}}{8 - 5e^{(3x)}} = $ help (fractions)

          Evaluate the limit.
(Use symbolic notation and fractions where needed.)
$\lim_{x \to -\infty} \frac{7 + 6e^{(2x)}}{8 - 5e^{(3x)}} = $ help (fractions)

$Evaluate the limit. (Use symbolic notation and fractions where needed.) limx → -∞(7 + 6e^(2x))/(8 - 5e^(3x)) = help (fractions)$

Added by Joaquin S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Kathleen Carty

04/10/2022

Step 1

The given limit expression can be rewritten as: lim_(x->-\infty) (7+6e^(2x))/(8-5e^(3x)) Show more…

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Evaluate the limit. (Use symbolic notation and fractions where needed.) lim_(x->-infty )(7+6e^((2x)))/(8-5e^((3x)))=, help (fractions) Evaluate the limit (Use symbolic notation and fractions where needed. lim7+6e(2r) x--008-5e3x help(fractions)