00:03
In this question we are given a function f x y z which is given by 1 upon root x square plus y square plus z square and we have to find out the triple integral of this at a distance which is given by center a sphere sorry sphere with radius 3.
00:34
So this is our given reason this is our given function.
00:45
So we know that triple integral we need to find out the volume of the triple integral.
00:49
So triple integral f of x y z into dv in spherical coordinates will be equal to triple integral f of phi and theta into r square sin phi and this is the dr d theta d phi.
01:15
This is the triple integral in spherical coordinates.
01:21
So now we will see our value of r theta and what is r what is theta and what is phi.
01:28
Since we are given that radius is given to be 3.
01:35
So therefore r lies between 0 to 3.
01:41
Right here is the reason radius will be 0 to 3 and we are given the bottom half only.
01:50
We are given the bottom half of the sphere.
01:59
So that will imply r angle phi will lies between phi by 2 to phi.
02:06
Alright and the sphere is given so r angle theta will lies between 0 to 2.
02:13
So now we will be integrating this.
02:17
So let me rename that as r phi is equal to triple integral f of x y z into dv that is equal to triple integral over the region r.
02:28
This is 1 upon root of x square plus y square plus z square into r square sin phi dr d theta d phi.
02:40
Alright so first of all we need to change this x square plus y square plus z square as well.
02:45
You know that in a sphere x square plus y square plus z square is equal to radius square...