'Ex: 16 A particle performing SHM. has a velocity of 10 m/s, when it crosses the mean position. If the amplitude of oscillation is 2 m, find the velocity when it is midway between mean and extreme position.'
Added by Silvia T.
Step 1
The maximum velocity is achieved at the mean position (equilibrium position), and it is given by \(v_{max} = \omega A\), where \(\omega\) is the angular frequency and \(A\) is the amplitude of the oscillation. Show more…
Show all steps
Close
Your feedback will help us improve your experience
Dwijendra Rao and 80 other Physics 103 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A particle is executing SHM with an amplitude of 4 cm. At the mean position, velocity of the particle is 10 cm/s. The distance of the particle from the mean position when its speed becomes 5 cm/s is
Aakash G.
A particle executing SHM has amplitude of 4 cm and its acceleration at a distance of 1 cm from the mean position is 3 cm s?². What will be its velocity be when it is at a distance of 2 cm from its mean position?
Geeta Y.
A particle is executing SHM with an amplitude of $4 \mathrm{~cm}$. At the mean position, velocity of the particle is $10 \mathrm{~cm} / \mathrm{s}$. The distance of the particle from the mean position when its speed becomes $5 \mathrm{~cm} / \mathrm{s}$ is (A) $\sqrt{3} \mathrm{~cm}$ (B) $\sqrt{5} \mathrm{~cm}$ (C) $2 \sqrt{3} \mathrm{~cm}$ (D) $2 \sqrt{5} \mathrm{~cm}$
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD