Find the inverse Laplace transform of the following functions: (i) 3/s + 2/(s - 4), (ii) 2s/(s^2 - 4), (iii) (s + 6)/(s^2 + 4), (iv) 12s/(s^2 - 5s + 6), (v) s^2/((2 + s)^2(3 + s)), (vi) (s - 1)/(s^2 + 6s + 13), (vii) (s + 3)/(s^2 - 4s + 13), (viii) (3s - 5)/((s - 4)(s + 3)), (ix) (s - 4)/((s + 5)(s - 2)), (x) (3s + 16)/(s^2 - 4), (xi) (3s - 2)/((s + 4)(s^2 - s)), (xii) s/(s^2 + 2), (xiii) 1/(s^2 + s - 12), (xiv) 1/(s^3 - 4s), (xv) (s^2 - 6s + 4)/(s^3 - 3s^2 + 2s).
Added by Ashley K.
Close
Step 1
So, the inverse Laplace transform of 3/(2s + 6) is 3/2 * e^(-3t). (ii) 128/(s^2 + 4) The inverse Laplace transform of 1/(s^2 + a^2) is sin(at). So, the inverse Laplace transform of 128/(s^2 + 4) is 64sin(2t). (iii) 8 - 4s^2/(4s^2 + 82) This function can be Show more…
Show all steps
Your feedback will help us improve your experience
Sri K and 77 other Calculus 3 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Determine the inverse Laplace transform of each of the following functions: a. F(s) = (s+1)e^(-4s) b. F(s) = (s+2)/(3s+1) c. F(s) = (s+4)/4 d. F(s) = (s^2+2)/(s+1)(s+3) e. F(s) = (s^3+2s^2+25)/10 f. F(s) = (s^2+2)/(s+1)(s+2) g. F(s) = (s+1)/(s^2+4s+8) h. F(s) = s/(s+12) i. F(s) = s/(s+13)
Madhur L.
What are the inverse Laplace transforms of the following functions? 1. F(s) = 6/(s^2+9) - 2/(s+4) + 5/s^4 2. F(s) = ((7s+6)/(s^2+2s))e^(-2s)
Adi S.
Homework 8: Inverse Laplace transforms 1. Determine the inverse Laplace transform of : a) X(s) = 3s + 4 / ((s + 1)(s + 2)) b) G(s) = 3(s + 4) / (s(s^2 + 6s + 8)(s + 10)) c) Y(s) = 3 / (s(s^2 + 6s + 10)) d) Y(s) = 3s + 2 / (s(s^2 + 10s + 74)) e) Y(s) = 2 / ((s + 1)(s^2 + 6s + 9))
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD