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Example 2: The data given in Table 3., were obtained for an anti-clockwise closed-loop traverse. The coordinates of the station A are E1500 m and N1500 m. Determine the correct coordinates of all the traverse stations after adjusting the traverse by: (i) Bowditch's method (ii) Transit rule. Table 3. Internal angles Length (m) Bearing $\angle A = 130^\circ 18' 45''$ $AB = 17.098$ $AF = 136^\circ 25' 12''$ $\angle B = 110^\circ 18' 23''$ $BC = 102.925$ $\angle C = 99^\circ 32' 35''$ $CD = 92.782$ $\angle D = 116^\circ 18' 02''$ $DE = 33.866$ $\angle E = 119^\circ 46' 07''$ $EF = 63.719$ $\angle F = 143^\circ 46' 20''$ $FA = 79.097$

          Example 2: The data given in Table 3., were obtained for an anti-clockwise closed-loop
traverse. The coordinates of the station A are E1500 m and N1500 m. Determine the
correct coordinates of all the traverse stations after adjusting the traverse by:
(i) Bowditch's method
(ii) Transit rule.
Table 3.
Internal angles
Length (m)
Bearing
$\angle A = 130^\circ 18' 45''$
$AB = 17.098$
$AF = 136^\circ 25' 12''$
$\angle B = 110^\circ 18' 23''$
$BC = 102.925$
$\angle C = 99^\circ 32' 35''$
$CD = 92.782$
$\angle D = 116^\circ 18' 02''$
$DE = 33.866$
$\angle E = 119^\circ 46' 07''$
$EF = 63.719$
$\angle F = 143^\circ 46' 20''$
$FA = 79.097$

Example 2: The data given in Table 3., were obtained for an anti-clockwise closed-loop
traverse. The coordinates of the station A are E1500 m and N1500 m. Determine the
correct coordinates of all the traverse stations after adjusting the traverse by:
(i) Bowditch's method
(ii) Transit rule.
Table 3.
Internal angles
Length (m)
Bearing
∠ A = 130^∘ 18' 45”
AB = 17.098
AF = 136^∘ 25' 12”
∠ B = 110^∘ 18' 23”
BC = 102.925
∠ C = 99^∘ 32' 35”
CD = 92.782
∠ D = 116^∘ 18' 02”
DE = 33.866
∠ E = 119^∘ 46' 07”
EF = 63.719
∠ F = 143^∘ 46' 20”
FA = 79.097

Added by Christina S.

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