Since it has a period of p = 2a, we can write it as:
g(t) = \frac{2t}{a} - 1, \quad 0 \le t \le a
g(t) = 3 - \frac{2t}{a}, \quad a \le t \le 2a
Now, we know that the derivative g'(t) is the square wave function from Example 6. Let's find g'(t):
g'(t) =
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