Find: Example For the network shown in the figure below The...

Find: Example For the network shown in the figure below The line currents The currents in each phase of \(\Delta\)-connected load The currents in each phase of Y-connected load The line voltages at the load. \(\bar{Z}_\Delta = 12 - j15 \Omega\) \(\bar{Z}_Y = 4 + j6 \Omega\) \(\bar{Z}_l = 2 \Omega\) \(\bar{V}_{ab} = 208 V\)

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00:01 As per the question we are given with three phases to start connected supply.

00:08 The number of phases given is 3.

00:14 Similarly, the voltage of this supply is given to us as, of this supply is equal to 230 volts.

00:26 This is a phase star, three phase star connected supply which is connected to, which is connected to a balanced data connected load, which looks something like this at this point.

00:45 Now similarly, this is connected here.

00:48 It is also given that load that is balanced, balanced delta connected load is equal to 15 kilowatt.

01:04 Now it is lagging factor, the lagging factor is 0 .8.

01:10 Now these are the things given to us in the question.

01:15 According to this, we need to first find the line current.

01:18 The line current, so to find the line current, we know that the given delta load is the balanced one.

01:29 Balanced delta connected load, connected load.

01:34 For this type of load, power or p is equal to under root 3 vlil for psi.

01:49 What is vl? that is the voltage of the load and current of the load.

01:54 Now we know that line voltage, line voltage or vl is equal to under root 3 vph.

02:06 Vph means for the phase voltage, phase voltage.

02:13 Therefore, it is under root 3.

02:15 Now this is already given to us in the question...

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