Step 1:
Given that the phase sequence is positive, we can find the phase voltages $\mathbf{V}_{B N}$ and $\mathbf{V}_{C N}$ as follows:
\begin{align*}
\mathbf{V}_{B N} &= \mathbf{V}_{A N} \angle -120^{\circ} = 440 \angle -60^{\circ} \, \mathrm{V} \\
\mathbf{V}_{C
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