Question

Example, Single loop circuit with two real batteries: The emfs and resistances in the circuit of Fig. 27-8a have the following values: $mathcal{E}_1 = 4.4 ext{ V}$, $mathcal{E}_2 = 2.1 ext{ V}$, $r_1 = 2.3 Omega$, $r_2 = 1.8 Omega$, $R = 5.5 Omega$. (a) What is the current $i$ in the circuit?

          Example, Single loop circuit with two real batteries:
The emfs and resistances in the circuit of Fig. 27-8a have the
following values:
$mathcal{E}_1 = 4.4 	ext{ V}$, $mathcal{E}_2 = 2.1 	ext{ V}$,
$r_1 = 2.3 Omega$, $r_2 = 1.8 Omega$, $R = 5.5 Omega$.
(a) What is the current $i$ in the circuit?

Example, Single loop circuit with two real batteries:
The emfs and resistances in the circuit of Fig. 27-8a have the
following values:
mathcalE1 = 4.4 ext V, mathcalE2 = 2.1 ext V,
r1 = 2.3 Omega, r2 = 1.8 Omega, R = 5.5 Omega.
(a) What is the current i in the circuit?

Added by Juan L.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

12/01/2022

Step 1

Since the batteries are connected in series, the total emf is the sum of the individual emfs. So, E = E1 + E2 = 44V + 21V = 65V. Show more…

Show all steps

Thanks for your feedback!

Example: Single loop circuit with two real batteries The emfs and resistances in the circuit of Fig 27-8a have the following values: E1 = 4.4 V, E2 = 2.1 V, r1 = 2.3 Ή, r2 = 1.8 Ή, R = 5.5 Ή (a) What is the current i in the circuit? E1 = 4.4, r1 = 2.3 E2 = 2.1, r2 = 1.8