1. In the triangular right-prism on the right: The sides of the equilateral triangle are 12 m. The height of the prism is 20 m. Determine the: a) volume of the prism b) surface area of the prism. 2. In the diagram on the right, KO = OM = 8 units, JO = 6 units, LO = 15 units, LR = 25 units and JL bisects KM perpendicularly. a) Classify JKLM. b) Determine the: i) area of JKLM ii) volume of the right-prism iii) lengths of JK and KL iv) total surface area of the right-prism.
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- The formula for the area of an equilateral triangle with side length \( a \) is: \[ \text{Area} = \frac{\sqrt{3}}{4} a^2 \] - Given \( a = 12 \) m: \[ \text{Area} = \frac{\sqrt{3}}{4} \times 12^2 = \frac{\sqrt{3}}{4} \times 144 = 36\sqrt{3} \text{ Show moreā¦
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The area of the base of a right equilateral triangular prism is $16 \sqrt{3} \mathrm{~cm}^{2}$. If the height of the prism is $12 \mathrm{~cm}$, then the lateral surface area and the total surface area of the prism respectively are (1) $288 \mathrm{~cm}^{2},(288+32 \sqrt{3}) \mathrm{cm}^{2}$ (2) $388 \mathrm{~cm}^{2},(388+32 \sqrt{3}) \mathrm{cm}^{2}$ (3) $288 \mathrm{~cm}^{2},(288+24 \sqrt{3}) \mathrm{cm}^{2}$ (4) $388 \mathrm{~cm}^{2},(388+24 \sqrt{3}) \mathrm{cm}^{2}$
Mohammed N.
The base of a right prism is an equilateral triangle of edge $12 \mathrm{~m}$. If the volume of the prism is $288 \sqrt{3} \mathrm{~m}^{3}$, then its height is (1) $6 \mathrm{~m}$ (2) $8 \mathrm{~m}$ (3) $10 \mathrm{~m}$ (4) $12 \mathrm{~m}$
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