Exercise: In the circuit below, $V_{TP} = -0.30\text{ V}$, and $K_p = 120\text{ }\mu A/V^2$. Calculate $V_{SG}$, $I_D$, and $V_{SD}$. $+2.2\text{ V}$ $R_1 = 255\text{ k}\Omega$ $R_S = 6\text{ k}\Omega$ $R_2 = 345\text{ k}\Omega$ $R_D = 42\text{ k}\Omega$ $-2.2\text{ V}$
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Calculate the voltage drop across Rs: VsG = Vp - Rs * K VsG = -0.30 V - (6kΩ * 120 A/V^2) VsG = -0.30 V - 720 V VsG = -720.30 V Show more…
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