Question

Exponential Application - Cooling The cooling of a cup of hot chocolate can be modeled by the function C(t) = 70 + 130e^{-0.02t}, where C(t) is the temperature in degrees Fahrenheit t minutes after the cup of hot chocolate was poured. How long will it take for the hot chocolate to reach a temperate of 160 degrees? A. 11.2 minutes B. 18.4 minutes C. 70.0 minutes D. 75.3 minutes E. 197.4 minutes

          Exponential Application - Cooling

The cooling of a cup of hot chocolate can be modeled by the function C(t) = 70 + 130e^{-0.02t}, where C(t) is the temperature in degrees Fahrenheit t minutes after the cup of hot chocolate was poured. How long will it take for the hot chocolate to reach a temperate of 160 degrees?

A. 11.2 minutes
B. 18.4 minutes
C. 70.0 minutes
D. 75.3 minutes
E. 197.4 minutes

Exponential Application - Cooling

The cooling of a cup of hot chocolate can be modeled by the function C(t) = 70 + 130e^-0.02t, where C(t) is the temperature in degrees Fahrenheit t minutes after the cup of hot chocolate was poured. How long will it take for the hot chocolate to reach a temperate of 160 degrees?

A. 11.2 minutes
B. 18.4 minutes
C. 70.0 minutes
D. 75.3 minutes
E. 197.4 minutes

Added by Kaitlin S.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Leigh Anne Emberg

05/25/2022

Step 1

02t) to find the time it takes for the hot chocolate to reach a temperature of 160 degrees: 160 = 70 + 130e^(0.02t) ** Show more…

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Exponential Application - Cooling The cooling of a cup of hot chocolate can be modeled by the function C(t) = 70 + 130e^{-0.02t}, where C(t) is the temperature in degrees Fahrenheit t minutes after the cup of hot chocolate was poured. How long will it take for the hot chocolate to reach a temperate of 160 degrees? A. 11.2 minutes B. 18.4 minutes C. 70.0 minutes D. 75.3 minutes E. 197.4 minutes