00:01
Hello everyone, in the first part of the question we are given with integral of 3x square plus x plus 5 divided by x square plus 3 into x minus 4 dx.
00:16
So, let us solve this integral value.
00:19
Now, let us take 3x square plus x plus 5 divided by x square plus 3 into x minus 4 will be equal to we can consider this as ax plus b divided by x square plus 3 plus c by x minus 4.
00:39
So, this can be written as ax plus b into x minus 4 plus c into x square plus 3 divided by x square plus 3 into x minus 4.
00:56
So, here we will have 3x square plus x plus 5 divided by x square plus 3 into x minus 4.
01:06
So, as we see here the denominator are equal so that we can equate the numerator to find the value of a b c.
01:13
So, that 3x square plus x plus 5 will be equal to ax plus b into x minus 4 plus c into x square plus 3.
01:28
Now, equating this and solving we will get a is equal to 0 b is equal to 1 and c is equal to 3.
01:39
Now, substituting those values in the equation we will get ax plus b divided by x square plus 3 plus c divided by x minus 4 will become 1 divided by x square plus 3 plus 3 divided by x minus 4.
02:04
Now, let us take the integration.
02:09
So, integrating 1 divided by x square plus 3 with respect to dx and integrating 3 divided by x minus 4 dx will give 1 by root 3 tan inverse of root 3 by 3 x plus 3 log x minus 4 plus.
02:42
So, the correct option from the following we can choose the answer is 3 log x minus 4 plus root 3 by 3 tan inverse of x root 3 by 3 plus c which is the answer for the first part of our question.
03:19
In the second part of the question we have to use trapezoidal rule to find the integral value of the given function.
03:32
So, by trapezoidal rule we have the formula that will be equal to delta x by 2 into f of x naught plus 2 f of x 1 plus etcetera plus 2 f of x n minus 1 plus f of x n...