F. Determine the solution of each 1. \( x^{2}+2 x+1>0 \) 2. \( 4 x^{2}<9 \) 3. \( (x-3)^{2} \geq 1 \)
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Step 1
Recognize that \(x^2 + 2x + 1\) is a perfect square: \((x+1)^2\). 2. Set up the inequality: \((x+1)^2 > 0\). 3. The square of a real number is zero only when the number itself is zero. Thus, \((x+1)^2 = 0\) when \(x = -1\). 4. Therefore, \((x+1)^2 > 0\) for all Show more…
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