00:01
This problem says for the following piecewise defined function, create a table of values from negative 4 to 4 for the x values, and then to sketch the graph.
00:08
And we're given f of x equals negative 4 when x is less than or equal to negative 2, x squared if negative 2 is less than x less than or equal to 2, and 4 if x is greater than 2.
00:19
So for our table of values when we evaluate we do need to plug in for the correct interval, so for negative 4 that's less than or equal to negative 2 which gives us the evaluation of just negative 4.
00:30
And that will be true of negative 3 and negative 2 as well because they are all also equal to, or less than or equal to negative 2.
00:38
But as soon as we hit negative 1 we get to our next interval because negative 1 is between negative 2 and less than or equal to 2.
00:45
So that's negative 1 squared which is 1, 0 squared is 1, or excuse me 0, and then 1 squared is 1, and then 2 squared will give us 4.
00:55
But that's our last evaluation because that's our last point in this interval where we're equal to 2.
00:59
Once we hit 3 we get to the evaluation of 4 for the last interval and that's 4 as the evaluation for the x value of 3 and for 4 there...