Question

The mass of polonium is given by the function $M_{Po}(t) = M_0 \left(\frac{1}{2}\right)^{\frac{t}{138}}$, where $M_0$ is the initial mass of polonium, in milligrams, and $M_{Po}$ is the mass, in milligrams, after $t$ days. At what rate is the polonium decaying when a sample has decayed to 75% of its initial mass?

          The mass of polonium is given by the function $M_{Po}(t) = M_0 \left(\frac{1}{2}\right)^{\frac{t}{138}}$,
where $M_0$ is the initial mass of polonium, in milligrams, and $M_{Po}$ is
the mass, in milligrams, after $t$ days. At what rate is the polonium
decaying when a sample has decayed to 75% of its initial mass?

The mass of polonium is given by the function MPo(t) = M0 ((1)/(2))^(t)/(138),
where M0 is the initial mass of polonium, in milligrams, and MPo is
the mass, in milligrams, after t days. At what rate is the polonium
decaying when a sample has decayed to 75% of its initial mass?

Added by Nathaniel N.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supratim Pal

Step 1

The equation for the decay of polonium can be written as: Mpo = o * (1 - r)^t where Mpo is the mass of polonium after t days, o is the initial mass of polonium, and r is the decay rate. Show more…

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Where o is the initial mass of polonium, in milligrams, and Mpo is the mass, in milligrams, after t days. At what rate is the polonium decaying when a sample has decayed to 75% of its initial mass?