Question

$F_{12} = \frac{Q_1 Q_2}{4\pi \epsilon_0 r_{12}^2}$ $= \frac{(5 \times 10^{-6})(-4 \times 10^{-6})(8.9875 \times 10^9)}{78}$ $\frac{7A_{m} + 2A_{g} - 5A_l}{\sqrt{78}}$

Name: f12 fracq1 q24pi epsilon0 r122 frac5 times 10 6 4 times 10 689875 times 10978 frac7am 2ag 5alsqrt78 10118
Uploaded: 2023-09-17T09:34:38-08:00
Duration: 8 min 49 s
Channel: David Morabito
Description: f12 fracq1 q24pi epsilon0 r122 frac5 times 10 6 4 times 10 689875 times 10978 frac7am 2ag 5alsqrt78 10118

          $F_{12} = \frac{Q_1 Q_2}{4\pi \epsilon_0 r_{12}^2}$
$= \frac{(5 \times 10^{-6})(-4 \times 10^{-6})(8.9875 \times 10^9)}{78}$
$\frac{7A_{m} + 2A_{g} - 5A_l}{\sqrt{78}}$

$f12 fracq1 q24pi epsilon0 r122 frac5 times 10 6 4 times 10 689875 times 10978 frac7am 2ag 5alsqrt78 10118$

Added by Sara A.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert David Morabito

09/17/2023

Step 1

The equation is: $F_{12} = \frac{Q_1 Q_2}{4\pi \epsilon_0 r_{12}^2}$ where: $F_{12}$ is the force between the two charges. $Q_1$ and $Q_2$ are the magnitudes of the two charges. $\epsilon_0$ is the permittivity of free space ($8.854 \times 10^{-12} \text{ Show more…

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$F_{12} = \frac{Q_1 Q_2}{4\pi \epsilon_0 r_{12}^2}$ $= \frac{(5 \times 10^{-6})(-4 \times 10^{-6})(8.9875 \times 10^9)}{78}$ $\frac{7A_{m} + 2A_{g} - 5A_l}{\sqrt{78}}$