Farmer moves along the boundary of a square field of side 10 m in 40 seconds. What will be the magnitude of displacement of the farmer at the end of 2 minutes and 20 seconds from his initial position?
Added by Alba M.
Step 1
The perimeter of the square field is 4 * 10 = 40 meters. The farmer moves along the boundary in 40 seconds, so his speed is: Speed = Distance / Time = 40 meters / 40 seconds = 1 meter/second Now, let's find out how many seconds are in 2 minutes and 20 Show more…
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A farmer moves along the boundary of a square field of side 10 meters in 40 seconds. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?
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