Fcr the next mechanism determine the angular acceleraon of link 3 and link 4and acceleration of point D.I @2=288 deg.83=66.878 deg.84=138.633 deg.w2=4 rad/sconstant CW,w3=1.198rad/sCW.and w4=1.237rad/sCCW
AB-12.5 BC-22.4" DC-27.9 CE=28.0
29.5 ay5ras2 a4-20/2
a3=-3ra a4=8racrs2 Acceleration of point D=149 inVs2
a37 rady2 a=12rag2
3=-10ra/s2 a4=-5rad/s2 OAcceleration of point D=111 irvg2
inVs2
in/s2