Question

Final Exam Find the magnitude of the vector sum \[ \vec{A}+\vec{B} \text {. } \] Vector \( A \) is \( 1,780 \mathrm{~m} \) long in a \( 13.6^{\circ} \) direction. Vector \( B \) is \( 0.438 \mathrm{~m} \) long in a \( 88.9^{\circ} \) direction.

          Final Exam
Find the magnitude of the vector sum
\[
\vec{A}+\vec{B} \text {. }
\]

Vector \( A \) is \( 1,780 \mathrm{~m} \) long in a \( 13.6^{\circ} \) direction.

Vector \( B \) is \( 0.438 \mathrm{~m} \) long in a \( 88.9^{\circ} \) direction.

Final Exam
Find the magnitude of the vector sum

A⃗+B⃗.

Vector A is 1,780 m long in a 13.6^∘ direction.

Vector B is 0.438 m long in a 88.9^∘ direction.

Added by James G.

College Physics

Roger A. Freedman; Todd Ruskell; Philip… 2nd Edition

Chapter 3

Instant Answer

Solved by Expert Zack A

Step 1

For vector \(\vec{A}\) and \(\vec{B}\), we will use the following formulas: \[ A_x = A \cos(\theta_A) \] \[ A_y = A \sin(\theta_A) \] \[ B_x = B \cos(\theta_B) \] \[ B_y = B \sin(\theta_B) \] Given: \[ A = 1780 \, \text{m}, \, \theta_A = 13.6^\circ \] \[ B = Show more…

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Final Exam Find the magnitude of the vector sum \[ \vec{A}+\vec{B} \text {. } \] Vector \( A \) is \( 1,780 \mathrm{~m} \) long in a \( 13.6^{\circ} \) direction. Vector \( B \) is \( 0.438 \mathrm{~m} \) long in a \( 88.9^{\circ} \) direction.